4.9x^2-22x+18=0

Solution for 4.9x^2-22x+18=0 equation:

4.9x^2-22x+18=0

a = 4.9; b = -22; c = +18;
Δ = b2-4ac
Δ = -222-4·4.9·18
Δ = 131.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-\sqrt{131.2}}{2*4.9}=\frac{22-\sqrt{131.2}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+\sqrt{131.2}}{2*4.9}=\frac{22+\sqrt{131.2}}{9.8}
$